0=x^2+22x+104

Solution for 0=x^2+22x+104 equation:

0=x^2+22x+104

We move all terms to the left:

0-(x^2+22x+104)=0

We add all the numbers together, and all the variables

-(x^2+22x+104)=0

We get rid of parentheses

-x^2-22x-104=0

We add all the numbers together, and all the variables

-1x^2-22x-104=0

a = -1; b = -22; c = -104;
Δ = b2-4ac
Δ = -222-4·(-1)·(-104)
Δ = 68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{68}=\sqrt{4*17}=\sqrt{4}*\sqrt{17}=2\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2\sqrt{17}}{2*-1}=\frac{22-2\sqrt{17}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2\sqrt{17}}{2*-1}=\frac{22+2\sqrt{17}}{-2}
$